Q:

Write the slope-intercept form of the equation of each line. Please show work.1) 2x − 3y = 242) 2x − y = 43) 7x − 5y = 354) x − y = 05) 4x − y = 26) 4x − 3y = −67) y + 4 = 1 2 (x − 2)8) y = − 5 2 (x + 2)9) y − 5 = −2(x + 2)10) y − 1 = 5(x − 1)11) y + 2 = 1 2 (x + 2)12) y − 4 = −(x − 4)

Accepted Solution

A:
Answer:12) [tex] y = -x + 8[/tex]11) [tex]y = 12x + 22[/tex]10) [tex]y = 5x - 4[/tex]9) [tex]y = -2x + 1[/tex]8) [tex]y = 2x + 9[/tex]7) [tex]y = 12x - 28[/tex]6) [tex]y = 1\frac{1}{3}x + 2[/tex]5) [tex]y = 4x - 2[/tex]4) [tex]y = x[/tex]3) [tex]y = 1\frac{2}{5}x - 7[/tex]2) [tex]y = 2x - 4[/tex]1) [tex]y = \frac{2}{3}x - 8[/tex]Step-by-step explanation:12)y - 4 = −(x - 4)y - 4 = −x + 4 + 4 + 4__________[tex]y = -x + 8[/tex]_____________________________________________11)y + 2 = 12(x + 2)y + 2 = 12x + 24 - 2 - 2____________[tex]y = 12x + 22[/tex]_____________________________________________10)y - 1 = 5(x - 1)y - 1 = 5x - 5 + 1 + 1_________[tex]y = 5x - 4[/tex]_____________________________________________9)y - 5 = −2(x + 2)y - 5 = −2x - 4 + 5 + 5__________[tex]y = -2x + 1[/tex]_____________________________________________8)y - 5 = 2(x + 2)y - 5 = 2x + 4 + 5 + 5__________[tex]y = 2x + 9[/tex]_____________________________________________7)y + 4 = 12(x - 2)y + 4 = 12x - 24 - 4 - 4____________[tex]y = 12x - 28[/tex]_____________________________________________6)4x - 3y = −6-4x - 4x________−3y = −4x - 6___ _____ −3 −3[tex]y = 1\frac{1}{3} + 2[/tex]_____________________________________________5)4x - y = 2-4x - 4x_______−y = −4x + 2[tex]y = 4x - 2[/tex]_____________________________________________4)x - y = 0______−y = −x[tex]y = x[/tex]_____________________________________________3)7x - 5y = 35-7x - 7x_________−5y = −7x + 35___ ______ −5 −5[tex]y = 1\frac{2}{5}x - 7[/tex]_____________________________________________2)2x - y = 4-2x - 2x_______−y = −2x + 4[tex]y = 2x - 4[/tex]_____________________________________________1)2x - 3y = 24-2x - 2x_________−3y = −2x + 24___ _______ −3 −3[tex]y = \frac{2}{3}x - 8[/tex]I am delighted to assist you anytime.